Hello Guys, How are you all? Hope You all Are Fine. Today When I execute my code in the safari browser I am facing the following error Invalid regular expression: invalid group specifier name in safari in Javascript. So Here I am Explain to you all the possible solutions here.
Without wasting your time, Let’s start This Article to Solve This Error.
How Invalid regular expression: invalid group specifier name in safari Error Occurs ?
When I execute my code in the safari browser I am facing the following error. In my Javascript code, this regex /(?<=\/)([^#]+)(?=#*)/
works fine in Chrome, but in safari, I get
Invalid regular expression: invalid group specifier name
How To Solve Invalid regular expression: invalid group specifier name in safari Error ?
How To Solve Invalid regular expression: invalid group specifier name in safari Error?
To Solve Invalid regular expression: invalid group specifier name in safari Error Here Safari doesn’t support look behind yet. One alternative would be to put the / that comes before in a non-captured group, and then extract only the first group (the content after the / and before the #). Also, (?=#) is odd – you probably want to look ahead for something, rather than a quantifier. It might be better to use something like. Just Use this.
Invalid regular expression: invalid group specifier name in safari
To Solve Invalid regular expression: invalid group specifier name in safari Error Here Safari doesn’t support look behind yet. One alternative would be to put the / that comes before in a non-captured group, and then extract only the first group (the content after the / and before the #). Also, (?=#) is odd – you probably want to look ahead for something, rather than a quantifier. It might be better to use something like. Just Use this.
Solution 1
Here Safari doesn’t support look behind yet. One alternative would be to put the /
that comes before in a non-captured group, and then extract only the first group (the content after the /
and before the #
).
/(?:\/)([^#]+)(?=#*)/
Also, (?=#*)
is odd – you probably want to look ahead for something, rather than a *
quantifier. It might be better to use something like. Just Use this.
/(?:\/)([^#]+)(?=#|$)/
or just omit the lookahead entirely, depending on your circumstances.
Summery
It’s all About this issue. Hope all solution helped you a lot. Comment below Your thoughts and your queries. Also, Comment below which solution worked for you?
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