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[Solved] Invalid regular expression: invalid group specifier name in safari

Hello Guys, How are you all? Hope You all Are Fine. Today When I execute my code in the safari browser I am facing the following error Invalid regular expression: invalid group specifier name in safari in Javascript. So Here I am Explain to you all the possible solutions here.

Without wasting your time, Let’s start This Article to Solve This Error.

How Invalid regular expression: invalid group specifier name in safari Error Occurs ?

When I execute my code in the safari browser I am facing the following error. In my Javascript code, this regex /(?<=\/)([^#]+)(?=#*)/ works fine in Chrome, but in safari, I get

Invalid regular expression: invalid group specifier name

How To Solve Invalid regular expression: invalid group specifier name in safari Error ?

  1. How To Solve Invalid regular expression: invalid group specifier name in safari Error?

    To Solve Invalid regular expression: invalid group specifier name in safari Error Here Safari doesn't support look behind yet. One alternative would be to put the / that comes before in a non-captured group, and then extract only the first group (the content after the / and before the #). Also, (?=#) is odd – you probably want to look ahead for something, rather than a  quantifier. It might be better to use something like. Just Use this.

  2. Invalid regular expression: invalid group specifier name in safari

    To Solve Invalid regular expression: invalid group specifier name in safari Error Here Safari doesn't support look behind yet. One alternative would be to put the / that comes before in a non-captured group, and then extract only the first group (the content after the / and before the #). Also, (?=#) is odd – you probably want to look ahead for something, rather than a  quantifier. It might be better to use something like. Just Use this.

Solution 1

Here Safari doesn’t support look behind yet. One alternative would be to put the / that comes before in a non-captured group, and then extract only the first group (the content after the / and before the #).

/(?:\/)([^#]+)(?=#*)/

Also, (?=#*) is odd – you probably want to look ahead for something, rather than a * quantifier. It might be better to use something like. Just Use this.

/(?:\/)([^#]+)(?=#|$)/

or just omit the lookahead entirely, depending on your circumstances.

Summery

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