close

[Solved] TypeScript – Element implicitly has an ‘any’ type because expression of type ‘string’ can’t be used to index type

Hello Guys, How are you all? Hope You all Are Fine. Today I am facing Following error TypeScript – Element implicitly has an ‘any’ type because expression of type ‘string’ can’t be used to index type in Javascript. So Here I am Explain to you all the possible solutions here.

Without wasting your time, Let’s start This Article to Solve This Error.

How TypeScript – Element implicitly has an ‘any’ type because expression of type ‘string’ can’t be used to index type Error Occurs ?

I Have this code.

const sub = {
    science: null,
    social: null,
    math: null
};

const newColor = ['science', 'social', 'math'].filter(e => sub[e]);

But I am facing this error.

Element implicitly has an 'any' type because expression of type 'string' can't be used to index type '{ science: null; social: null; math: null; }'. No index signature with a parameter of type 'string' was found on type '{ science: null; social: null; math: null; }'.

How To Solve TypeScript – Element implicitly has an ‘any’ type because expression of type ‘string’ can’t be used to index type Error ?

  1. How To Solve TypeScript – Element implicitly has an 'any' type because expression of type 'string' can't be used to index type Error?

    To Solve TypeScript – Element implicitly has an 'any' type because expression of type 'string' can't be used to index type Error The as const causes the compiler to infer a tuple composed of exactly the three string literals in the array, in the exact order you've set. (It's even a read-only tuple). That is good enough to fix your error:

  2. TypeScript – Element implicitly has an 'any' type because expression of type 'string' can't be used to index type

    To Solve TypeScript – Element implicitly has an 'any' type because expression of type 'string' can't be used to index type Error The as const causes the compiler to infer a tuple composed of exactly the three string literals in the array, in the exact order you've set. (It's even a read-only tuple). That is good enough to fix your error:

Solution 1

You can declare sub as any to tell TypeScript to get off your back on this one (aka explicit any):

const sub : any = {
    science: null,
    social: null,
    math: null
};

But if possible, strong typing is preferable:

const sub : { [key: string]: any } = {
    science: null,
    social: null,
    math: null
};

Solution 2

Assuming you’re using TS3.4 or later, the easiest way to get this kind of type inference from the compiler is to use an const assertion:

const constAssertionTest = ["science", "social", "math"] as const;

The as const causes the compiler to infer a tuple composed of exactly the three string literals in the array, in the exact order you’ve set. (It’s even a read-only tuple). That is good enough to fix your error:

const newColor = (["science", "social", "math"] as const).filter(e => sub[e]); // this is fine

Summery

It’s all About this issue. Hope all solution helped you a lot. Comment below Your thoughts and your queries. Also, Comment below which solution worked for you?

Also Read

Please Rate Our Solution to Motivate Us For Give Our Best

Leave a Comment